The first ionisation energy of oxygen is less | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The electronic configuration of nitrogen $(N)$ is $1s^2 2s^2 2p^3$,which is a stable half-filled $p$-orbital configuration.Oxygen $(O)$ has the co

Vedclass · Accepted Answer

Greater inter-electron repulsion between two electrons in the same $p$-orbital counter balances the increase in effective nuclear charge on moving from nitrogen to oxygen

Vedclass · Answer

(C) The electronic configuration of nitrogen $(N)$ is $1s^2 2s^2 2p^3$,which is a stable half-filled $p$-orbital configuration.Oxygen $(O)$ has the configuration $1s^2 2s^2 2p^4$.Although oxygen has a higher effective nuclear charge than nitrogen,the $2p^4$ configuration of oxygen experiences greater inter-electron repulsion between two electrons in the same $p$-orbital.This repulsion makes it easier to remove an electron from oxygen compared to the stable half-filled configuration of nitrogen,thus resulting in a lower first ionisation energy for oxygen.

The first ionisation energy of oxygen is less than that of nitrogen. Which of the following is the correct reason for this observation?

Similar Questions

Among $Be$, $B$, $Mg$ and $Al$, the second ionisation potential is maximum for

Which of the following processes will have the maximum ionization energy?

The first ionization energy of boron is less than that of beryllium because

The correct trend in the first ionization enthalpies of the elements in the $3^{rd}$ period of periodic table is:

With reference to the concept of ionisation potential,which one of the following sets is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module